x^2+1x+112=0

Solution for x^2+1x+112=0 equation:

Simplifying
x2 + 1x + 112 = 0

Reorder the terms:
112 + 1x + x2 = 0

Solving
112 + 1x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-112' to each side of the equation.
112 + 1x + -112 + x2 = 0 + -112

Reorder the terms:
112 + -112 + 1x + x2 = 0 + -112

Combine like terms: 112 + -112 = 0
0 + 1x + x2 = 0 + -112
1x + x2 = 0 + -112

Combine like terms: 0 + -112 = -112
1x + x2 = -112

The x term is 1x.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
x + 0.25 + x2 = -112 + 0.25

Reorder the terms:
0.25 + x + x2 = -112 + 0.25

Combine like terms: -112 + 0.25 = -111.75
0.25 + x + x2 = -111.75

Factor a perfect square on the left side:
(x + 0.5)(x + 0.5) = -111.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.